Wednesday, 08/29/2012

Courtesy TribeAthletics.com
Former William and Mary women's tennis standout Megan Moulton-Levy will compete in her second Grand Slam event of the year and her first career U.S. Open on Wednesday, Aug. 29. Moulton-Levy and doubles partner Lindsay Lee-Waters were added to the doubles draw on Tuesday and will face off against 13-time Grand Slam doubles champions Serena and Venus Williams. The match will be played on the Grandstand court and not before 3 p.m. on Wednesday.

Moulton-Levy and Lee-Waters will compete in their third Grand Slam event, having played in the main draw of the Championships at Wimbledon each of the last two years. The pair is coming off a semifinal performance in a WTA event, the New Haven Open at Yale, last week. Earlier this year, Moulton-Levy and Lee-Waters won an ITF event in Osprey, Fla., marking Moulton-Levy's 10th career ITF doubles event title. Moulton-Levy is currently ranked a career-best No. 87 in the WTA World Doubles Rankings.

The Williams sisters have won the U.S. Open twice during their careers in 1999 and 2009. They claimed the title the last time they competed as a doubles team in the U.S. Open and are coming off both an Olympic Gold Medal and the Wimbledon doubles crown.

One of the most decorated players in W&M and CAA history, Moulton-Levy was a two-time winner of the ITA National Arthur Ashe Jr. Award for Leadership and Sportsmanship. A four-time CAA Player of the Year and six-time All-American, Moulton-Levy won the most combined (singles and doubles) matches in school history at 249. She still ranks second in program annals with 125 doubles wins, third in singles wins (124) and singles winning percentage (.775) along with being fifth on the doubles winning percentage list (.758). In 2007, Moulton-Levy teamed with 2009 graduate Katarina Zoricic to win the ITA National Indoor Doubles Championship and advance to the finals of the NCAA Doubles Championship.